Find the moment of inertia of a solid sphere of mass `M` and radius `R` about an axis XX shown in figure. Also find radius of gyration about the given axis.

Explanation

From theorem of parallel axes, the moment of inertia of solid sphere of mass is
.
`I_(XX')=I_(CM)+MR^(2)`
`=(2)/(5)MR^(2)+MR^(2)=(7)/(5)MR^(2)=(7)/(5)(5)(2)^(2)=28 "kg-m"^(2)`.