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At any instant, a rolling body may be co...

At any instant, a rolling body may be considered to be in pure rotation about an axis through the point of contact. This axis is translating forward with speed

A

equal to centre of mass

B

zero

C

twice of centre of mass

D

None of these

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem regarding the rolling body and its instantaneous axis of rotation, we can break down the explanation into clear steps: ### Step-by-Step Solution: 1. **Understanding Pure Rolling Motion**: - A rolling body is one that rolls without slipping. This means that the point of contact with the ground does not slide; it has zero velocity relative to the ground. 2. **Identifying the Instantaneous Axis of Rotation**: - For a rolling object, at any instant, we can consider the axis of rotation to be at the point of contact with the ground. This is known as the instantaneous axis of rotation. 3. **Velocity of the Center of Mass**: - The center of mass of the rolling body moves forward with a certain velocity (let’s denote it as \( v_{cm} \)). For pure rolling motion, the velocity of the point of contact (which is at rest relative to the ground) must equal zero. 4. **Condition for Pure Rolling**: - The condition for pure rolling is that the velocity of the center of mass is equal to the product of the angular velocity (\( \omega \)) and the radius (\( r \)) of the body: \[ v_{cm} = \omega \cdot r \] - This means that the point of contact has a velocity of zero when the body rolls without slipping. 5. **Translating Axis of Rotation**: - The axis of rotation is translating forward with the speed of the center of mass. Thus, if the body rolls forward, the instantaneous axis of rotation moves forward at the same speed as the center of mass. 6. **Conclusion**: - Therefore, the condition for the body to be in pure rotation about the instantaneous axis through the point of contact is that the velocity of the center of mass must equal the velocity of the point of contact, which is zero at that instant. ### Final Answer: - The correct option is that the velocity of the point of contact is equal to the velocity of the center of mass when the axis is translating forward with speed. ---

To solve the problem regarding the rolling body and its instantaneous axis of rotation, we can break down the explanation into clear steps: ### Step-by-Step Solution: 1. **Understanding Pure Rolling Motion**: - A rolling body is one that rolls without slipping. This means that the point of contact with the ground does not slide; it has zero velocity relative to the ground. 2. **Identifying the Instantaneous Axis of Rotation**: ...
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The general motion of a rigid body can be considered to be a combination of (i) a motion of its centre of mass about an axis, and (ii) its motion about an instantaneous exis passing through the centre of mass. These axes need not be stationary. Consider, for example, a thin uniform disc welded (rigidly fixed) horizontally at its rim to a massless, stick as shown in the figure. When the disc-stick system is rotated about the origin on a horizontal frictionless plane with angular speed omega the motion at any instant can be taken as a combination of (i) a rotation of the disc through an instantaneous vertical axis passing through its centre of mass (as is seen from the changed orientation of points P and Q). Both these motions have the same angular speed omega in this case Now consider two similar system as shown in the figure: Case (a) the disc with its face vertical and parallel to x-z plane, Case (b) the disc with its face making an angle of 45^@ with x-y plane and its horizontal diameter parallel to x-axis. In both the cases, the disc is welded at point P, and the systems are rotated with constant angular speed omega about the z-axis. Which of the following statements regarding the angular speed about the instantaneous axis (passing through the centre of mass) is correct?

The general motion of a rigid body can be considered to be a combination of (i) a motion of its centre of mass about an axis, and (ii) its motion about an instantaneous exis passing through the centre of mass. These axes need not be stationary. Consider, for example, a thin uniform disc welded (rigidly fixed) horizontally at its rim to a massless, stick as shown in the figure. When the disc-stick system is rotated about the origin on a horizontal frictionless plane with angular speed omega the motion at any instant can be taken as a combination of (i) a rotation of the disc through an instantaneous vertical axis passing through its centre of mass (as is seen from the changed orientation of points P and Q). Both these motions have the same angular speed omega in this case Now consider two similar system as shown in the figure: Case (a) the disc with its face vertical and parallel to x-z plane, Case (b) the disc with its face making an angle of 45^@ with x-y plane and its horizontal diameter parallel to x-axis. In both the cases, the disc is welded at point P, and the systems are rotated with constant angular speed omega about the z-axis. . Which of the following statements about the instantaneous axis (passing through the centre of mass) is correct?

Knowledge Check

  • (1) Centre of gravity (C.G.) of a body is the point at which the weight of the body acts, (2) Centre of mass coincides with the centre of gravity if the earth is assumed to have infinitely large radius, (3) To evaluate the gravitational field intensity due to any body at an external point, the entire mass of the body can be considered to be concentrated at its C.G.., (4) The radius of gyration of any body rotating about an axis is the length of the perpendicular dropped from the C.G. of the body to the axis. which one of the following pairs of statements is correct ?

    A
    (1) and (4)
    B
    (1) and (2)
    C
    (1) and (3)
    D
    (3) and (4)
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