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A ring and a disc of different masses ar...

A ring and a disc of different masses are rotating with the same kinetic energy. If we apply a retarding torque `tau` on the ring, it stops after making n revolution. After how many revolutions will the disc stop, if the retarding torque on it is also `tau` ?

A

`(n)/(2)`

B

`n`

C

`2n`

D

Data insufficient

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The correct Answer is:
To solve the problem, we need to analyze the situation involving the ring and the disc that are rotating with the same kinetic energy and are subjected to the same retarding torque. ### Step-by-Step Solution: 1. **Understanding Kinetic Energy**: - The kinetic energy (KE) of a rotating object is given by the formula: \[ KE = \frac{1}{2} I \omega^2 \] - Where \(I\) is the moment of inertia and \(\omega\) is the angular velocity. 2. **Setting Up the Problem**: - Let the kinetic energy of the ring be \(KE_R\) and the kinetic energy of the disc be \(KE_D\). - According to the problem, \(KE_R = KE_D\). 3. **Applying Retarding Torque**: - When a retarding torque \(\tau\) is applied, the work done by the torque is equal to the change in kinetic energy. - For the ring: \[ \text{Work done} = \tau \cdot \theta_R = \Delta KE_R = KE_R - 0 = KE_R \] - For the disc: \[ \text{Work done} = \tau \cdot \theta_D = \Delta KE_D = KE_D - 0 = KE_D \] 4. **Relating Angular Displacement to Revolutions**: - The angular displacement in terms of revolutions is given by: \[ \theta = n \cdot 2\pi \] - Therefore, for the ring: \[ \tau \cdot (n \cdot 2\pi) = KE_R \] - And for the disc, let the number of revolutions be \(n'\): \[ \tau \cdot (n' \cdot 2\pi) = KE_D \] 5. **Equating Work Done**: - Since \(KE_R = KE_D\), we can equate the work done by the torque on both the ring and the disc: \[ \tau \cdot (n \cdot 2\pi) = \tau \cdot (n' \cdot 2\pi) \] 6. **Canceling Common Terms**: - We can cancel \(\tau\) and \(2\pi\) from both sides: \[ n = n' \] 7. **Conclusion**: - Therefore, the number of revolutions \(n'\) that the disc makes before stopping is equal to \(n\): \[ n' = n \] ### Final Answer: The disc will also stop after making \(n\) revolutions. ---

To solve the problem, we need to analyze the situation involving the ring and the disc that are rotating with the same kinetic energy and are subjected to the same retarding torque. ### Step-by-Step Solution: 1. **Understanding Kinetic Energy**: - The kinetic energy (KE) of a rotating object is given by the formula: \[ KE = \frac{1}{2} I \omega^2 ...
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  2. A rigid body rotates with an angular momentum L. If its rotational kin...

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  7. The figure shows the angular velocity versus time graph of a flywheel....

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  9. A sphere can roll on a surface inclined at an angle theta if the frict...

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  10. If a disc of mass m and radius r is reshaped into a ring of radius2r, ...

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  11. A disc of mass m and radius R is rolling on horizontal ground with lin...

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  12. Two discs have same mass and thickness. Their materials are of densiti...

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  13. A ball rolls without slipping. The radius of gyration of the ball abou...

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  14. The speed of a homogenous solid sphere after rolling down an inclined ...

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  15. Consider three solid spheres, sphere (i) has radius r and mass m, sphe...

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  16. The moment of inertia of a system of four rods, each of length l and m...

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  17. the density of a non-uniform rod of length 1 m is given by rh...

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  18. ABC is right angled triangular plane of uniform thickness The sides ar...

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