ABC is right angled triangular plane of uniform thickness The sides are such that AB gt BC as sshown in figure `I_(1),I_(2),I_(3)` are moments of inertia about AB, BC and AC, respectively.Then which of the following relations is correct?

Options

A. `I_(1)=I_(2)=I_(3)`
B. `I_(2) gt I_(1) gt I_(3)`
C. `I_(3) lt I_(2) lt I_(1)`
D. `I_(2) gt I_(1) gt I_(2)`

Answer

B

Explanation

For a given body, mass is same, so it will depend only on the distribution of mass about the axis
The mass is farthest from axis BC, so `I_(2)` is maximum. Mass is nearest to axis AC, so `I_(3)` is minimum.
Hence, the correct sequence will be
`I_(2) gt I_(1) gt I_(3)`