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The moment of inertia of a cube of mass ...

The moment of inertia of a cube of mass m and side a about one of its edges is equal to

A

`(2)/(3) ma^(2)`

B

`(4)/(3)ma^(2)`

C

`3ma^(2)`

D

`(8)/(3)ma^(2)`

Text Solution

Verified by Experts

The correct Answer is:
A

From theorem of perpendicular axes, we have
`I=I_(c)+m((a)/(sqrt(2)))^(2)=((ma^(2))/(12)+(ma^(2))/(12))+(ma^(2))/(2)=(2)/(3)ma^(2)`.
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