A piece of blue glass heated to a high temperature and a piece of red glass at room temperature, are taken inside a dimly lit room then

Options

A. the blue piece will look blue and red will look as usual
B. red looks brighter red and blue looks ordinary blue
C. blue shines like brigher red compared to the red piece
D. Both the pieces will look equally red

Explanation

To solve the problem, we need to analyze the behavior of the two pieces of glass when placed in a dimly lit room. Here’s a step-by-step solution:

### Step 1: Identify the properties of the glasses
- **Blue Glass**: Heated to a high temperature.
- **Red Glass**: At room temperature.

### Step 2: Understand the effect of temperature on color perception
- The blue glass, when heated, will absorb certain wavelengths of light. Specifically, it will absorb wavelengths that are longer than blue (which includes red).

### Step 3: Analyze the behavior of the red glass
- The red glass remains at room temperature, meaning it does not emit any additional light or change its color. It will appear red in the dimly lit room.

### Step 4: Analyze the behavior of the blue glass
- The heated blue glass will absorb red light due to its high temperature. It will then emit light as it cools down. The emission will include red wavelengths because it absorbs them.

### Step 5: Compare the brightness of the two glasses
- Since the blue glass is emitting red light (after absorbing it), it will appear brighter than the red glass, which is simply reflecting the red light without any additional emission.

### Step 6: Conclusion
- The blue glass will shine brighter in red compared to the red glass itself because it is actively emitting red light after absorbing it.

### Final Answer
The correct option is that the blue glass shines brighter red compared to the red piece.

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