A body of mass 6 kg is acted on a by a force so that its velocity changes from `3 ms^(-1)` to `5ms^(-1)`, then change in momentum is

Options

A. 48 Ns
B. 24 Ns
C. 30 Ns
D. 12 Ns

Explanation

To solve the problem of finding the change in momentum of a body with a mass of 6 kg, whose velocity changes from 3 m/s to 5 m/s, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Given Values:**
- Mass of the body (m) = 6 kg
- Initial velocity (u) = 3 m/s
- Final velocity (v) = 5 m/s

2. **Calculate Initial Momentum (P_initial):**
- The formula for momentum (P) is given by:
\[ P = m \times v \]
- Therefore, the initial momentum is:
\[ P_{\text{initial}} = m \times u = 6 \, \text{kg} \times 3 \, \text{m/s} = 18 \, \text{kg m/s} \]

3. **Calculate Final Momentum (P_final):**
- Using the same formula for momentum, the final momentum is:
\[ P_{\text{final}} = m \times v = 6 \, \text{kg} \times 5 \, \text{m/s} = 30 \, \text{kg m/s} \]

4. **Calculate Change in Momentum (ΔP):**
- The change in momentum is given by:
\[ \Delta P = P_{\text{final}} - P_{\text{initial}} \]
- Substituting the values we calculated:
\[ \Delta P = 30 \, \text{kg m/s} - 18 \, \text{kg m/s} = 12 \, \text{kg m/s} \]

5. **Convert to Newton-seconds:**
- Since 1 kg m/s is equivalent to 1 Newton second, we can say:
\[ \Delta P = 12 \, \text{Newton seconds} \]

### Final Answer:
The change in momentum is **12 Newton seconds**.