A block of mass `200kg` is set into motion on a frictionless , horizontal surface with the help of frictionless pulley and a rope system as shown in figure. What horizontal force `F` should be applied to produce in the block an acceleration of `1 m//s^(2)`?

Options

A. 50 N
B. 100 N
C. 200 N
D. 10 N

Answer

B

Explanation

(b) As shown in figure, when force F is applied at the end of the string, the tension in the lower part of the string is also F. If T is the tension in string connecting the pulley and the block, then,

T=2F
But T=ma = (200)(1)=200 N
`therefore` 2F 200N or F=100 N