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A hockey player is moving northward and ...

A hockey player is moving northward and suddenly turns westward with the same speed to avoid an opponet. The force that acts on the player is.

A

frictional force along westward

B

muscle force along southward

C

frictional force along south-west

D

muscle force along south-west

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The correct Answer is:
To solve the problem of the hockey player turning from moving northward to westward, we need to analyze the situation in terms of momentum and the change in direction. Here’s a step-by-step solution: ### Step 1: Understand the Initial and Final Directions The hockey player is initially moving northward. We can represent this direction as a vector pointing upwards on a graph. When the player turns westward, the direction changes to the left on the graph. **Hint:** Visualize the directions on a coordinate system where north is up and west is left. ### Step 2: Represent the Initial and Final Momentum Let’s denote the initial momentum of the player moving northward as \( P_1 \) and the final momentum when the player turns westward as \( P_2 \). Since the speed remains the same, the magnitudes of these momentum vectors will be equal, but their directions will differ. **Hint:** Remember that momentum is a vector quantity, which means it has both magnitude and direction. ### Step 3: Draw the Vectors Draw a diagram where: - The vector \( P_1 \) points north (upward). - The vector \( P_2 \) points west (to the left). This creates a right-angled triangle where the change in momentum can be visualized. **Hint:** Use arrows to represent the direction and length of the momentum vectors accurately. ### Step 4: Calculate the Change in Momentum The change in momentum \( \Delta P \) can be calculated as: \[ \Delta P = P_2 - P_1 \] Since the player is changing direction, the resultant vector will be diagonal, pointing southwest. **Hint:** The change in momentum is not just a simple subtraction; consider the vector nature of momentum. ### Step 5: Determine the Direction of the Resultant Force The resultant change in momentum will point towards the southwest direction because the player is moving from north to west. According to Newton's second law, the force acting on the player is in the direction of the change in momentum. **Hint:** The direction of the force is always in the direction of the change in momentum. ### Conclusion The force that acts on the player as they turn from north to west is directed towards the southwest. **Final Answer:** The force that acts on the player is directed southwest.

To solve the problem of the hockey player turning from moving northward to westward, we need to analyze the situation in terms of momentum and the change in direction. Here’s a step-by-step solution: ### Step 1: Understand the Initial and Final Directions The hockey player is initially moving northward. We can represent this direction as a vector pointing upwards on a graph. When the player turns westward, the direction changes to the left on the graph. **Hint:** Visualize the directions on a coordinate system where north is up and west is left. ### Step 2: Represent the Initial and Final Momentum ...
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DC PANDEY ENGLISH-LAWS OF MOTION-Chapter exercises (A) Taking it together
  1. A metre scale is moving with uniform velocity. This implies .

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  2. Conservation of momentum in a collision between particles can be under...

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  3. A hockey player is moving northward and suddenly turns westward with t...

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  4. If the elevator in shown figure is moving upwards with constant accele...

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  5. A block can slide on a smooth inclined plane of inclination theta kept...

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  6. A car of mass m starts from rest and acquires a velocity along east up...

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  7. A cricket ball of mass 150 g has an intial velocity u = (3 hati + 4 ha...

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  8. In the previous problem (3) , the magnitude of the momentum transferre...

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  9. In the figure show , a person wants to raise a block lying on the grou...

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  10. A body of mass 2kg travels according to the law x(t) = pt + qt^(2) + r...

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  11. A body with mass 5 kg is acted upon by a force vec(F) = (- 3 hat (i) +...

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  12. A block of mass m is placed on a smooth inclined plane of inclination ...

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  13. A block has been placed on an inclined plane . The slope angle of thet...

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  14. A 5000 kg rocket is set for vertical firing. The exhaust speed is 800 ...

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  15. Two blocks are in contact on a frictionless table. One has mass m and ...

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  16. A 4 kg block A is placed on the top of 8 kg block B which rests on a s...

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  17. Find the value of friction forces between the blocks A and B and betwe...

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  18. A block of mass 5 kg is kept on a horizontal floor having coefficient ...

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  19. Two masses A and B of 10 kg and 5 kg respectively are connected with a...

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  20. Two blocks of masses 2m and m are in equilibrium a shown in the figure...

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