If the coefficient of friction between `A` and `B` is `mu`, the maximum acceleration of the wedge `A` for which `B` will remain at rest with respect to the wedge is

Options

A. `mug`
B. `g((1+mu)/(1-mu))`
C. `g((1-mu)/(1+mu))`
D. `(g)/(mu)`

Answer

B

Explanation

(b) `N sin theta+ mu N cos theta=ma`

`N cos theta+ mu N sin theta=ma`
Putting `theta=45^(@)` and solving these two equations , we get
`a=g((1+mu)/(1-mu))`