A block of mass 1 kg is at rest relative to a smooth wedge moving leftwards with constant acceleration`a=5m//s^(2)` Let N be the normal reaction between block and the wedge .Then `(g=10m//s^(2)`)

Options

A. `N=5sqrt(5)N`
B. `N=15 N`
C. `tan theta=(1)/(2)`
D. `tan theta=2`

Answer

A, C

Explanation

(a,c) `N sin theta=ma=1xx5=5`……..(i)
`N cos theta=mg=1xx10=10`…..(ii)
From these two equations, we get
`N=5sqrt(5) N`(Adding and squaring them)
and `" " tan theta=(1)/(2)`