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Two blocks of masses m =5kg and M =10kg ...

Two blocks of masses `m =5kg and M =10kg` are connected by a string passing over a pulley `B` as shown. Another string connect the center of pulley `B` to the floor and passes over another pulley `A` as shown. An upwards force `F` is applied at the center of pulley `A`. Both the pulleys are massless.
Find the acceleration of block `m` and `M`, if `F` is
(a) `100N`
`300N`
`500N(Take g = 10m//s^(2))`

A

`5 ms^(-2)`,zero

B

zero,`5 ms^(-2)`

C

zero,zero

D

`5 ms^(-2),5 ms^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
A

(a)`(F)/(4)=75 N` or`(F)/(4)lt100N`

Therefore, `a_(M)=0`
`a_(m)=(75-50)/(5)=5m//s^(2)`
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