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A man of mass m stands on a platform of ...

A man of mass `m` stands on a platform of equal mass `m` and pulls himself by two ropes passing over pulleys as shown in figure.If he pulls each rope with a force equal to half his weight ,his upwards acceleration would be

A

`(g)/(2)`

B

`(g)/(4)`

C

g

D

zero

Text Solution

Verified by Experts

The correct Answer is:
D
(d) Total upward force`=2((mg)/(2))=mg`
[Weight of man is balanced by total tension acting upwards]
Total downward force is also mg
`therefore " " F_("net")=0=a_("net")`
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