A block of mass m is given an initial downward velocity `v_(0)` and left on inclined place ( coefficient of friction =0.6). The block will

Options

A. continue of move down the plane with constant velocity `v_(0)`
B. accelerate downward
C. decelerate and come to rest
D. first accelerate downward then decelerate

Answer

C

Explanation

( c) `f_("max")=mu mg cos thet=0.6xxmgxx(sqrt(3))/(2)=0.52 mg `

Since ,`f_("max")gt mg sin theta`
Block will decelerate and come to rest.