A block of mass m slides down an incline...

A block of mass m slides down an inclined plane of inclination `theta` with uniform speed. The coefficient of friction between the block and the plane is `mu`. The contact force between the block and the plane is

`mu mg`

`mu mg sin theta`

`mu (mg sin theta-mg cos theta)`

`mg sin theta`

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The correct Answer is:

(d) Block is a rest. Hence, `f=mg sin theta`

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