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A block of mass m is thrown upwards with...

A block of mass m is thrown upwards with some initial velocity as shown in figure. On the block

`{:("Column I","Column II"),("(A) Net force in horizontal direction","(p) Zero"),("(B) Net force in vertical direction",(q) m(g sin theta+mug cos theta)),("(C) Net force along the plane",(r)m(g sin theta cos theta+mu g cos^(2) theta)),("(D) Net force perpendicular to plane",(s)m(g sin^(2) theta+mug sin theta cos theta)):}`

Text Solution

Verified by Experts

The correct Answer is:
A`rarr`r,B`rarr`s,C`rarr`q,D `rarr`p
Force of friction and `mg sin theta` both are downwards.
`therefore` Acceleration of the block is `a=(g sin theta+mu g cos theta)` down the plane
Now, net force in any direction is equal to, F=m(component of acceleration in that direction)
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