A 3 kg block is placed over a 10 kg block and both are palced on a smooth horizontal surface. The coefficient of friction between the block is 0.2 . If a horizontal force of 20 N is applied to 3 kg block, accelerations of the two block in `ms^(-2)` are (take, `g=ms^(-2)`)

Options

A. `(13)/(4),0.6`
B. `(14)/(4),3`
C. `(13)/(4),3`
D. `(14)/(3),0.6`

Answer

D

Explanation

(d) We know that F-f=ma
Here for small body,
`a_(1)=(20-0.2xx3xx10)/(3) implies a_(1)=(14)/(3) ms^(-2)`
Similarly, `0.2xx3xx10=10xxa_(2)`
`a_(2)=(6)/(10)=0.6 ms^(-2)`