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A body floats in water with 40% of its v...

A body floats in water with 40% of its volume outside water. When the same body floats in an oil. 60% of its volume remians outside oil. The relative density of oil is

A

`0.9`

B

`1.0`

C

`1.2`

D

`1.5`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to use the principle of buoyancy, which states that the weight of the fluid displaced by a floating body is equal to the weight of the body itself. ### Step-by-step Solution: 1. **Understanding the Problem**: - The body floats in water with 40% of its volume above the water surface. This means that 60% of its volume is submerged in water. - When the body floats in oil, 60% of its volume is above the oil surface, meaning that 40% of its volume is submerged in oil. 2. **Setting Up the Equations**: - Let \( V \) be the total volume of the body. - The density of water is \( \rho_1 \) (approximately \( 1000 \, \text{kg/m}^3 \)). - The density of oil is \( \rho_2 \). - The volume submerged in water is \( 0.6V \) and the volume submerged in oil is \( 0.4V \). 3. **Applying the Principle of Buoyancy**: - The weight of the body is equal to the weight of the water displaced: \[ \text{Weight of body} = \text{Weight of water displaced} \] \[ mg = (0.6V) \rho_1 g \] - The weight of the body can also be expressed in terms of its density \( \sigma_1 \) (density of the body): \[ mg = V \sigma_1 g \] - Equating the two expressions: \[ V \sigma_1 g = (0.6V) \rho_1 g \] - Canceling \( Vg \) from both sides: \[ \sigma_1 = 0.6 \rho_1 \] 4. **For the Oil**: - Similarly, for the oil: \[ mg = (0.4V) \rho_2 g \] - Again, equating the weight of the body: \[ V \sigma_1 g = (0.4V) \rho_2 g \] - Canceling \( Vg \): \[ \sigma_1 = 0.4 \rho_2 \] 5. **Relating the Densities**: - Now we have two equations for \( \sigma_1 \): \[ 0.6 \rho_1 = 0.4 \rho_2 \] - Rearranging gives: \[ \frac{\rho_2}{\rho_1} = \frac{0.6}{0.4} = 1.5 \] 6. **Finding the Relative Density of Oil**: - The relative density of oil is defined as: \[ \text{Relative Density of Oil} = \frac{\rho_2}{\rho_1} \] - From our calculation, we find: \[ \text{Relative Density of Oil} = 1.5 \] ### Final Answer: The relative density of oil is **1.5**.

To solve the problem, we need to use the principle of buoyancy, which states that the weight of the fluid displaced by a floating body is equal to the weight of the body itself. ### Step-by-step Solution: 1. **Understanding the Problem**: - The body floats in water with 40% of its volume above the water surface. This means that 60% of its volume is submerged in water. - When the body floats in oil, 60% of its volume is above the oil surface, meaning that 40% of its volume is submerged in oil. ...
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