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A hole is made at the bottom of the tank...

A hole is made at the bottom of the tank filled with water (density `=1000 kgm^(-3))`. If the total pressure at the bottom of the tank is three atmospheres (1 atmosphere `=10^(5) Nm^(-2))`, then the velocity of efflux is nearest to

A

`sqrt(400) ms^(-1)`

B

`sqrt(200) ms^(-1)`

C

`sqrt(600) ms^(-1)`

D

`sqrt(500) ms^(-1)`

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The correct Answer is:
To solve the problem of finding the velocity of efflux from a hole at the bottom of a tank filled with water, we can use Bernoulli's principle. Here's a step-by-step solution: ### Step 1: Understand the Given Information - Density of water, \( \rho = 1000 \, \text{kg/m}^3 \) - Total pressure at the bottom of the tank, \( P = 3 \, \text{atmospheres} \) - Conversion of atmospheric pressure: \( 1 \, \text{atmosphere} = 10^5 \, \text{N/m}^2 \) ### Step 2: Calculate Total Pressure in Pascals Convert the total pressure from atmospheres to Pascals: \[ P = 3 \, \text{atmospheres} = 3 \times 10^5 \, \text{N/m}^2 = 300000 \, \text{N/m}^2 \] ### Step 3: Apply Bernoulli’s Equation According to Bernoulli's principle, the pressure energy per unit volume is converted to kinetic energy per unit volume. The equation can be expressed as: \[ \Delta P = \frac{1}{2} \rho v^2 \] Where \( \Delta P \) is the pressure difference and \( v \) is the velocity of efflux. ### Step 4: Determine the Pressure Difference Since the pressure at the surface of the water is atmospheric pressure (1 atmosphere), the pressure difference \( \Delta P \) at the hole is: \[ \Delta P = P - P_{\text{atmospheric}} = 3 \times 10^5 \, \text{N/m}^2 - 1 \times 10^5 \, \text{N/m}^2 = 2 \times 10^5 \, \text{N/m}^2 \] ### Step 5: Substitute Values into the Equation Now, substitute \( \Delta P \) into Bernoulli's equation: \[ 2 \times 10^5 = \frac{1}{2} \times 1000 \times v^2 \] ### Step 6: Solve for Velocity \( v \) Rearranging the equation to solve for \( v^2 \): \[ v^2 = \frac{2 \times 2 \times 10^5}{1000} \] \[ v^2 = \frac{4 \times 10^5}{1000} = 400 \] Taking the square root: \[ v = \sqrt{400} = 20 \, \text{m/s} \] ### Final Answer The velocity of efflux is nearest to: \[ \boxed{20 \, \text{m/s}} \]

To solve the problem of finding the velocity of efflux from a hole at the bottom of a tank filled with water, we can use Bernoulli's principle. Here's a step-by-step solution: ### Step 1: Understand the Given Information - Density of water, \( \rho = 1000 \, \text{kg/m}^3 \) - Total pressure at the bottom of the tank, \( P = 3 \, \text{atmospheres} \) - Conversion of atmospheric pressure: \( 1 \, \text{atmosphere} = 10^5 \, \text{N/m}^2 \) ### Step 2: Calculate Total Pressure in Pascals ...
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