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The pressure of water in a pipe when tap...

The pressure of water in a pipe when tap is closed is `5.5xx10^(5) Nm^(-2)`. The velocity with which water comes out on opening the tap is

A

`10 ms^(-1)`

B

`5 ms^(-1)`

C

`20 ms^(-1)`

D

`15 ms^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
Decrese in pressure energy = increase in kinetic energy
`or" "Deltarho=1/2rhov^(2)`
`therefore" " v=sqrt((2(DeltaP))/rho)=sqrt((2xx0.5xx10^(5))/(10^(3)))=10 ms^(-1)`
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