Water flows along horizontal pipe whose cross-section is not constant. The pressureis 1 cam of Hg, where the veloecity is 35 cm/s . At a point where the velocity is 65cm/s then pressure will be

Options

A. 0.89 cm of Hg
B. 0.62 cm of Hg
C. 0.5 cm of Hg
D. 1 cm of Hg

Answer

A

Explanation

Applying Bernoulli's equation, we get
`p_(1)+1/2rhov_(1)^(2)=p_(2)+1/2rhov_(2)^(2)`
`or" "(10^(-2)xx13.6xx10^(3)xx10)+1/2xx10^(3)xx(0.35)^(2)`
`=p_(2)+1/2xx10^(3)xx(0.65)^(2)`
`or" "p_(2)=1210Nm^(-2)=(1210xx10^(2))/(13.6xx10^(3)xx10)" cm of Hg"`
=0.89 cm of Hg