For a body immersed in a liquid, when the weight of the body is less than the upthrust then the body will

Options

A. float partially immersed
B. sink
C. float full immersed
D. both (a) and (c )

Explanation

To solve the question, we need to analyze the forces acting on a body immersed in a liquid, specifically focusing on the relationship between the weight of the body and the buoyant force (upthrust) acting on it.

### Step-by-Step Solution:

1. **Understand the Forces Involved**:
- When a body is immersed in a liquid, two main forces act on it:
- The weight of the body (mg), which acts downwards.
- The buoyant force (upthrust), which acts upwards.

2. **Identify the Condition Given**:
- The question states that the weight of the body (mg) is less than the upthrust (buoyant force). Mathematically, this can be expressed as:
\[ mg < F_b \]
where \( F_b \) is the buoyant force.

3. **Apply Archimedes' Principle**:
- According to Archimedes' principle, the buoyant force acting on a body immersed in a fluid is equal to the weight of the fluid displaced by the body.

4. **Analyze the Implications of the Condition**:
- When the weight of the body is less than the buoyant force, it means that the upward force (buoyant force) is greater than the downward force (weight of the body).

5. **Determine the Body's Behavior**:
- Since the buoyant force is greater than the weight, the body will experience a net upward force. This causes the body to rise until it either floats completely on the surface of the liquid or is partially immersed.

6. **Conclusion**:
- The body will float or be partially immersed in the liquid. Thus, the correct answer to the question is that the body will float or be partially immersed.

### Final Answer:
The body will float or be partially immersed in the liquid.

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