Water falls from a tap with `A_(0)=4 m^(2)`, `A=1 m^(2)` and h=2 m, then velocity v is

Options

A. `A_(0) sqrt((2ghA^(2))/(A_(0)^(2)-A^(2)))`
B. `2A_(0) sqrt((ghA^(2))/(A_(0)^(2)-A^(2)))`
C. `A_(0)sqrt((gh)/(2))`
D. `2A sqrt((ghA_(0)^(2))/(A_(0)^(2)-A^(2)))`

Answer

A

Explanation

As,`A_(0)v_(0)=Av implies v^(2)=v_(0)^(2)+2gh`
`implies v_(0) =sqrt((2ghA^(2))/(A_(0)^(2)-A^(2))) " or" R=A_(0)v_(0)=A_(0)sqrt((2ghA^(2))/(A_(0)^(2)-A^(2)))`