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A water drop of radius 10^-2 m is broken...

A water drop of radius `10^-2` m is broken into 1000 equal droplets. Calculate the gain in surface energy. Surface tension of water is `0.075Nm^-1`

A

`16.96xx10^(-4) J`

B

`8.48 xx 10^(-4) J`

C

`4.24 xx 10^(-4) J`

D

`2.12 xx 10^(-4) J`

Text Solution

Verified by Experts

The correct Answer is:
B
Gain in surface energy
`E=4piR^(2)(n^(1/3)-1)T`
`=4 xx 3.14 xx (10^(-2))(1000)^(1//3)-1 xx 0.075`
`=8.48 xx 10^(-4)` J
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