The horizontal component of the earth's magnetic field at a place is `4.0xx10^(-4)`T and the dip is `45^(@)`. A metal rod of length 20 cm is placed in the north-south direction and is moved at a constant speed of 5 cm/s towards east. Calculate the emf induced in the rod.

Explanation

To solve the problem, we will follow these steps:

### Step 1: Identify the given values
- Horizontal component of the Earth's magnetic field, \( H = 4.0 \times 10^{-4} \, \text{T} \)
- Angle of dip, \( \delta = 45^\circ \)
- Length of the rod, \( L = 20 \, \text{cm} = 0.2 \, \text{m} \)
- Speed of the rod, \( v = 5 \, \text{cm/s} = 5 \times 10^{-2} \, \text{m/s} \)

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