Two coils having self-inductances, `L_(1)=5mH` and `L_(2)=1mH`. The current in the coil is increasing of same constant rate at a certain instant and the power supplied to the coils is also same, Find the ratio of
(i) induced voltage
(ii) current
(iii) energy stored in two coils at that instant

Explanation

To solve the problem step by step, we will analyze the given information and apply the relevant formulas.

### Given:
- Self-inductance of coil 1, \( L_1 = 5 \, \text{mH} = 5 \times 10^{-3} \, \text{H} \)
- Self-inductance of coil 2, \( L_2 = 1 \, \text{mH} = 1 \times 10^{-3} \, \text{H} \)
- The rate of change of current in both coils is the same, \( \frac{di_1}{dt} = \frac{di_2}{dt} \)
- The power supplied to both coils is the same, \( P_1 = P_2 \)

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