Self - inductance `0.8xx10^(-4)`H of a uniformly wound solenoid, having resistance 3 `Omega` is broken up into two indentical coils. Those coils are connected in series across a 6 V battery of negligible resistance. Find time constant and steady state current.

Explanation

To solve the problem, we need to find the time constant and steady-state current for the given solenoid after it has been broken into two identical coils and connected in series across a battery.

### Step-by-Step Solution:

1. **Identify Given Values:**
- Self-inductance of the solenoid, \( L = 0.8 \times 10^{-4} \, \text{H} \)
- Resistance of the solenoid, \( R = 3 \, \Omega \)
- Voltage of the battery, \( V = 6 \, \text{V} \)
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