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The dimensions of magnetic flux are...

The dimensions of magnetic flux are

A

`[MLT^(-2)A^(-2)]`

B

`[ML^(2)T^(-2)A^(-2)]`

C

`[ML^(2)T^(-1)A^(-2)]`

D

`[ML^(2)T^(-2)A^(-1)]`

Text Solution

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The correct Answer is:
To find the dimensions of magnetic flux, we can follow these steps: ### Step 1: Understand the Definition of Magnetic Flux Magnetic flux (Φ) is defined as the product of the magnetic field (B) and the area (A) through which the field lines pass. Mathematically, it can be expressed as: \[ \Phi = B \cdot A \] ### Step 2: Determine the Dimensions of Magnetic Field (B) To find the dimensions of magnetic flux, we first need the dimensions of the magnetic field (B). We can use the formula for the magnetic force on a charge moving in a magnetic field: \[ F = Q (v \times B) \] Where: - \( F \) = force - \( Q \) = charge - \( v \) = velocity - \( B \) = magnetic field From this equation, we can express the dimensions of the magnetic field (B): \[ [F] = [Q] \cdot [v] \cdot [B] \] Rearranging gives: \[ [B] = \frac{[F]}{[Q] \cdot [v]} \] ### Step 3: Substitute Dimensions Now we substitute the dimensions of force, charge, and velocity: - The dimensional formula for force \( [F] \) is \( [M L T^{-2}] \). - The dimensional formula for charge \( [Q] \) is \( [I T] \) (where \( I \) is current). - The dimensional formula for velocity \( [v] \) is \( [L T^{-1}] \). Substituting these into the equation for \( B \): \[ [B] = \frac{[M L T^{-2}]}{[I T] \cdot [L T^{-1}]} \] This simplifies to: \[ [B] = \frac{M L T^{-2}}{I L T^{-1}} = \frac{M}{I T} \] ### Step 4: Find Dimensions of Area (A) The area (A) has the dimensional formula: \[ [A] = [L^2] \] ### Step 5: Combine to Find Dimensions of Magnetic Flux (Φ) Now we can find the dimensions of magnetic flux: \[ [\Phi] = [B] \cdot [A] \] Substituting the dimensions we found: \[ [\Phi] = \left(\frac{M}{I T}\right) \cdot [L^2] \] This gives: \[ [\Phi] = \frac{M L^2}{I T} \] ### Step 6: Final Expression Thus, the final dimensional formula for magnetic flux is: \[ [\Phi] = M L^2 T^{-2} I^{-1} \] ### Conclusion The dimensions of magnetic flux are: \[ [M L^2 T^{-2} I^{-1}] \]

To find the dimensions of magnetic flux, we can follow these steps: ### Step 1: Understand the Definition of Magnetic Flux Magnetic flux (Φ) is defined as the product of the magnetic field (B) and the area (A) through which the field lines pass. Mathematically, it can be expressed as: \[ \Phi = B \cdot A \] ...
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DC PANDEY ENGLISH-ELECTROMAGNETIC INDUCTION-Check point
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  4. The magnetic flux linked with a coil, in webers is given by the equati...

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  5. A coil having an area A(0) is placed in a magnetic field which changes...

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  6. The magnetic flux phi (in weber ) in a closed circuit of resistance 10...

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  8. The magnetic flux across a loop of resistance 10Omega is given by phi=...

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  9. A circular ring of diameter 20cm has a resistance 0.01Omega How much c...

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  10. Magnetic flux in a circuite containing a coil of resistance 2Omegachan...

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  11. The direction of induced e.m.f. during electromagnetic induction is gi...

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  12. Two different wire loops are concentric and lie in the same plane. The...

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  13. Lenz's law is consequence of the law of conservation of

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  14. The north pole of a long horizontal bar magnet is being brought closer...

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  15. There is a uniform magnetic field directed perpendicular and into the ...

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  16. A conducing rod of length l is falling with a velocity v perpendicular...

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  17. A wire of length 50 cm moves with a velocity of 300 m/min, perpendicul...

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  18. A 10 m wire kept in east-west direction is falling with velocity 5 m/s...

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  19. A boat is moving due east in a region where the earth's magnetic field...

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  20. The magnitude of the earth's magnetic field at a place is B(0) and an...

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