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During current growth in an L-R circuit ...

During current growth in an L-R circuit the time constant is the time in which the magnitude of current becomes

A

`i_(0)`

B

`i_(0)//2`

C

`0.63i_(0)`

D

`0.37i_(0)`

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The correct Answer is:
To solve the question regarding the time constant in an L-R circuit, we will go through the following steps: ### Step 1: Understand the L-R Circuit An L-R circuit consists of an inductor (L) and a resistor (R) connected in series with a battery of electromotive force (E). The inductor stores energy in the magnetic field when current flows through it, while the resistor dissipates energy as heat. **Hint:** Remember that the inductor's behavior is characterized by its inductance (L) and the resistor's behavior is characterized by its resistance (R). ### Step 2: Define the Current in the Circuit The current (I) at any time (t) in the L-R circuit can be expressed by the formula: \[ I(t) = I_0 \left(1 - e^{-\frac{R t}{L}}\right) \] where: - \( I_0 \) is the maximum current (steady-state current) given by \( I_0 = \frac{E}{R} \), - \( e \) is the base of the natural logarithm. **Hint:** The term \( e^{-\frac{R t}{L}} \) represents the exponential decay of the current growth in the circuit. ### Step 3: Define the Time Constant The time constant (\( \tau_L \)) for an L-R circuit is defined as: \[ \tau_L = \frac{L}{R} \] This time constant indicates the time it takes for the current to reach approximately 63.2% of its maximum value (\( I_0 \)). **Hint:** The time constant is a crucial parameter that helps in understanding how quickly the circuit responds to changes in voltage. ### Step 4: Calculate the Current at One Time Constant To find the current at one time constant (\( t = \tau_L \)): \[ I(\tau_L) = I_0 \left(1 - e^{-1}\right) \] Since \( e^{-1} \) is approximately 0.3679, we can calculate: \[ I(\tau_L) = I_0 \left(1 - 0.3679\right) \] \[ I(\tau_L) \approx I_0 \times 0.6321 \] **Hint:** The value \( 1 - e^{-1} \) gives you the fraction of the maximum current reached after one time constant. ### Step 5: Conclusion After one time constant, the magnitude of the current becomes approximately 0.63 times the initial current \( I_0 \). Thus, the correct answer to the question is: \[ \text{Current at } \tau_L = 0.63 I_0 \] **Final Answer:** The time constant is the time in which the magnitude of current becomes \( 0.63 I_0 \).

To solve the question regarding the time constant in an L-R circuit, we will go through the following steps: ### Step 1: Understand the L-R Circuit An L-R circuit consists of an inductor (L) and a resistor (R) connected in series with a battery of electromotive force (E). The inductor stores energy in the magnetic field when current flows through it, while the resistor dissipates energy as heat. **Hint:** Remember that the inductor's behavior is characterized by its inductance (L) and the resistor's behavior is characterized by its resistance (R). ### Step 2: Define the Current in the Circuit ...
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