Two identical circular loops of metal wire are lying on a table without touching each other. Loop-A carries a current which increases with time. In response, the loop-B

Options

A. remains stationary
B. is attracted by loop A
C. is repelled by loop A
D. rotates about its centre of mass with CM fixed

Explanation

To solve the problem, we will analyze the situation step by step using the principles of electromagnetic induction, specifically applying Faraday's law and Lenz's law.

### Step-by-Step Solution:

1. **Identify the Setup**: We have two identical circular loops of wire, Loop-A and Loop-B, placed on a table without touching each other. Loop-A carries a current that is increasing with time.

2. **Determine the Magnetic Field**: When current flows through Loop-A, it generates a magnetic field around it. The direction of the magnetic field can be determined using the right-hand rule. If the current in Loop-A is flowing in a certain direction (let's assume counterclockwise), the magnetic field lines will point upwards through the center of the loop.

3. **Change in Magnetic Flux**: As the current in Loop-A increases, the strength of the magnetic field produced by Loop-A also increases. This leads to an increase in the magnetic flux through Loop-B, which is positioned nearby.

4. **Apply Faraday's Law of Induction**: According to Faraday's law, a change in magnetic flux through a loop induces an electromotive force (EMF) in that loop. The induced EMF in Loop-B is proportional to the rate of change of magnetic flux through it.

5. **Determine the Direction of Induced Current**: According to Lenz's law, the direction of the induced current in Loop-B will be such that it opposes the change in magnetic flux. Since the magnetic flux through Loop-B is increasing (due to the increasing current in Loop-A), the induced current in Loop-B will flow in a direction that creates a magnetic field opposing the increase.

6. **Conclusion on Induced Current Direction**: If the magnetic field from Loop-A is directed upwards (due to the current in Loop-A), Loop-B will induce a current that flows in the same direction as Loop-A to oppose the increase in upward magnetic flux. Therefore, the induced current in Loop-B will also flow counterclockwise.

7. **Determine the Interaction Between the Loops**: Since the currents in Loop-A and Loop-B are in the same direction (both counterclockwise), they will attract each other. This is due to the fact that parallel currents attract each other.

### Final Answer:
The induced current in Loop-B will flow in the same direction as the current in Loop-A (counterclockwise), and Loop-B will be attracted to Loop-A.