The network shown in the figure is part of a complete circuit. If at a certain instant, the current `I` is `5A` and is decreasing at a rate `10^(3)A//s` then `V_(B)-V_(A)` is

Options

A. 5 V
B. 10 V
C. 15 V
D. 20 V

Answer

C

Explanation

Applying Kirchhoff's second law to above ciruit,

`V_(A)-iR+15-L(di)/(dt)=V_(B)`
or `V_(A)-5xx1+15-(5xx10^(-3))(-10^(3))=V_(B)`
`therefore" "V_(B)-V_(A)=15 V`