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The loop shown moves with a velocity v i...

The loop shown moves with a velocity `v` in a uniform magnetic field of magnitude `B`, directed into the paper. The potential differene between point `P` and `Q` is e. Then

A e=12BLv
B e=BLv
C P is positive with respect to Q
D Q is positive with respect to P

A

(ii), (iii)

B

(i), (iv)

C

(i), (iii)

D

(ii), (iv)

Text Solution

Verified by Experts

The correct Answer is:
C

`V_(P)+(e)/(4)-e+(e)/(4)=V_(Q)rArrV_(P)-V_(Q)=-(e)/(2)=(BLv)/(2)`
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