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shows a conducting loop being pulled out of a magnetic field with a speed v. Which of lthe four plots shown in may represent the power delivered by the pulling agent as a function of the speed v ?
a
b
c
d

A

a

B

b

C

c

D

d

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The correct Answer is:
To solve the problem of determining which plot represents the power delivered by the pulling agent as a function of speed \( v \) for a conducting loop being pulled out of a magnetic field, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Induced EMF**: The induced electromotive force (EMF) in the loop can be expressed using Faraday's law of electromagnetic induction. For a loop being pulled out of a magnetic field with a velocity \( v \), the induced EMF (\( \mathcal{E} \)) is given by: \[ \mathcal{E} = B \cdot L \cdot v \] where \( B \) is the magnetic field strength, \( L \) is the length of the loop, and \( v \) is the velocity. **Hint**: Remember that the induced EMF is directly proportional to the velocity of the loop. 2. **Calculate the Power**: The power (\( P \)) delivered by the pulling agent can be calculated using the formula: \[ P = \frac{\mathcal{E}^2}{R} \] where \( R \) is the resistance of the loop. Substituting the expression for EMF, we get: \[ P = \frac{(B \cdot L \cdot v)^2}{R} \] 3. **Simplify the Power Expression**: Simplifying the expression for power, we have: \[ P = \frac{B^2 \cdot L^2 \cdot v^2}{R} \] This shows that power \( P \) is proportional to the square of the velocity: \[ P \propto v^2 \] **Hint**: Identify the relationship between power and velocity; it is quadratic. 4. **Determine the Graph Shape**: Since \( P \) is proportional to \( v^2 \), the graph of power versus velocity will be a parabola opening upwards. This means as the velocity increases, the power increases with the square of the velocity. 5. **Select the Correct Plot**: Among the given options (a, b, c, d), we need to identify which one represents a parabolic relationship. The correct plot will show a curve that starts at the origin and rises steeply as \( v \) increases. **Hint**: Look for a graph that resembles a quadratic function, typically shaped like a "U". ### Conclusion: Based on the analysis, the correct option that represents the power delivered by the pulling agent as a function of speed \( v \) is **option B**, which shows a parabolic relationship.

To solve the problem of determining which plot represents the power delivered by the pulling agent as a function of speed \( v \) for a conducting loop being pulled out of a magnetic field, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Induced EMF**: The induced electromotive force (EMF) in the loop can be expressed using Faraday's law of electromagnetic induction. For a loop being pulled out of a magnetic field with a velocity \( v \), the induced EMF (\( \mathcal{E} \)) is given by: \[ \mathcal{E} = B \cdot L \cdot v ...
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