Light of wavelength 300 nm in medium A enters into medium B througha plane surface. If frequency of light is `5xx10^(14)` Hz and `v_(a)//v_(b)=4//5`, then find absolute refractive indices of media A and B.

Explanation

To find the absolute refractive indices of media A and B, we can follow these steps:

### Step-by-Step Solution:

1. **Identify Given Values:**
- Wavelength in medium A, \( \lambda_A = 300 \, \text{nm} = 300 \times 10^{-9} \, \text{m} \)
- Frequency of light, \( f = 5 \times 10^{14} \, \text{Hz} \)
- Ratio of velocities, \( \frac{v_A}{v_B} = \frac{4}{5} \)
...