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An isotropic point source is placed at a...

An isotropic point source is placed at a depth h below the water surface. A floating opaque disc is placed on the surface of water so that the source is not visible from the surface. What is the minimum radius of the disc? Take refractive index of `"water"=mu`.

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To solve the problem of finding the minimum radius of the opaque disc placed on the water surface such that an isotropic point source at a depth \( h \) below the surface is not visible, we can follow these steps: ### Step 1: Understanding the Critical Angle The critical angle \( \theta_c \) is the angle of incidence above which total internal reflection occurs. For light traveling from water to air, the critical angle can be determined using Snell's law: \[ \sin \theta_c = \frac{1}{\mu} \] ...
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DC PANDEY ENGLISH-RAY OPTICS-Medical entrance gallary
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  2. Two identical glass (mu(g)=3//2) equi- convex lenses of focal length f...

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  3. An air bubble in a glass slab with refractive index 1.5 (near normal i...

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  6. Match the corresponding entries of Column I with Column II.

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  8. Two identical thin planoconvex glass lenses (refractive index 1.5) eac...

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  12. Angle of minimum deviation for a prism of refractive index 1.5 is equa...

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  14. The focal length of a converting lens are f(v) and f(r) for violet and...

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  17. If mu(v)=1.530 and mu(R)=1.5145, then disperisve power of a crown glas...

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  19. Calculate the focal length of a reading glass of a person, if the dist...

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  21. The magnification power of a convex lens of focal length 10cm, when th...

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