An object of size `3.0 cm` is placed `14 cm` in front of a concave lens of focal length `21 cm`. Describe the image produced by the lens. What happens if the object is moved further from the lens ?

Explanation

To solve the problem step by step, we will use the lens formula and the magnification formula for a concave lens.

### Step 1: Identify the given values
- Object size (height, \( h_o \)) = 3.0 cm
- Object distance (\( u \)) = -14 cm (negative because the object is in front of the lens)
- Focal length (\( f \)) = -21 cm (negative for concave lens)

### Step 2: Use the lens formula
...