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The angle of minimum deviation for a gla...

The angle of minimum deviation for a glass prism with `mu=sqrt3` equals the refracting angle of the prism. What is the angle of the prism?

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To solve the problem, we need to find the angle of the prism (let's denote it as \( A \)) given that the angle of minimum deviation (\( D_{min} \)) is equal to the refracting angle of the prism and the refractive index (\( \mu \)) is \( \sqrt{3} \). ### Step-by-Step Solution: 1. **Understanding the Relationship**: We know that for a prism, the relationship between the refractive index (\( \mu \)), the angle of minimum deviation (\( D_{min} \)), and the angle of the prism (\( A \)) is given by: \[ \mu = \frac{\sin\left(\frac{D_{min} + A}{2}\right)}{\sin\left(\frac{A}{2}\right)} ...
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