A small telescope has an objective lens of focal length 144 cm and an eye piece of focal length `6.0 cm`. What is the separation between the objective and the eye piece ?

Explanation

M=magnifying power of telescope
L=seperation between the objective and the eyepiece
In norma ladjustment(i.e., when the final image is formed at `oo`),
`M=(f_(o))/(f_(e))=-144/6=-24rArrM=24`
`L=f_(o)+f_(e)=144^=150 cm`