The eyepice of an astronomicasl telescope has a focasl length of 10 cm. The telescope is focussed for normal vision of distant objects when the tube length is 1.0 m. find the focal length of the bjective and the magnifying power of the telescope.

Explanation

Given, `f_(e)=10 cm, L_(oo)=1.0m=100cm`
Since, `L_(oo)=f_(o)+f_(e)`
`therefore f_(o)=90.0 cm`
Further, magnification, `M_(oo)=(f_(o))/(f_(e))=90.0/10.0=9.0`