if separation of two energy levels in an atom is `2.3eV`, when the frequency of radiation emitted when the atom transits from the upper level to the lower level is

Explanation

Here, difference of energy
`Delta=2.3 eV=2.3xx1.6xx10^(-19) J`
and Planck's constant `h=6.62xx10^(-34) J-s " " [ :. 1 eV =1.6xx10^(-19) J]`
Using the relation, `hv=DetlaE=E_(2)-E_(1)`
or `" " v=(DeltaE)/(h)=(2.3xx1.6xx10^(-19))/(6.62xx10^(-34))`
`0.553xx10^(15)Hz~~5.6xx10^(14) Hz`