Use Moseley's law with b = 1 to find the frequency of the `K_alpha` X-ray of `La(Z = 57)` if the frequency of the `K_alpha` X-ray of `Cu(Z = 29)` is known to be `1*88 xx 10^(18)` Hz.

Explanation

To find the frequency of the `K_alpha` X-ray of Lanthanum (La, Z = 57) using Moseley's law, we will follow these steps:

### Step 1: Write down Moseley's Law
Moseley's law states that the frequency of the X-ray emitted is proportional to the square of the atomic number (Z) of the element, given by the formula:
\[ \sqrt{f} = a(Z - b) \]
where \( f \) is the frequency, \( a \) is a constant, \( Z \) is the atomic number, and \( b \) is a constant (given as 1 in this case).
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