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Two beams of light having intensities I and 4I interfere to produce a fringe pattern on a screen. The phase difference between the beams is `pi//2` at point A and `pi` at point B. Then, difference between the resultant intensities at A and B is

A

`2I`

B

`4I`

C

`5I`

D

`9I`

Text Solution

Verified by Experts

The correct Answer is:
B
`DeltaI=(I_(1)+I_(2)+2sqrt(I_(1)I_(2))cosphi_(1))-(I_(1)+I_(2)+2sqrt(I_(1)I_(2))cosphi_(2))`
`=2sqrt(I_(1)I_(2))(cosphi_(1)-cosphi_(2))=2xx2I("cos"phi/2-cospi)=4I`
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