Home
Class 12
PHYSICS
Assertion Two coherent sources transmit ...

Assertion Two coherent sources transmit waves of equal intensity `I_(0)` Resultant intensity at a point where path difference is `lambda/3` is also `I_(0)`.
Reason In interference resultant intensity at any point is the average intensity of two individual intensities.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question, we need to analyze both the assertion and the reason provided in the context of wave optics, specifically interference. ### Step-by-Step Solution: 1. **Understanding the Assertion**: - The assertion states that two coherent sources transmit waves of equal intensity \( I_0 \), and at a point where the path difference is \( \frac{\lambda}{3} \), the resultant intensity is also \( I_0 \). 2. **Path Difference and Phase Difference**: - The path difference \( \Delta x \) is given as \( \frac{\lambda}{3} \). - The phase difference \( \phi \) can be calculated using the formula: \[ \phi = \frac{2\pi}{\lambda} \Delta x \] - Substituting \( \Delta x = \frac{\lambda}{3} \): \[ \phi = \frac{2\pi}{\lambda} \cdot \frac{\lambda}{3} = \frac{2\pi}{3} \] 3. **Calculating Resultant Intensity**: - The resultant intensity \( I \) for two coherent sources can be expressed as: \[ I = I_1 + I_2 + 2\sqrt{I_1 I_2} \cos(\phi) \] - Since both sources have equal intensity \( I_1 = I_2 = I_0 \): \[ I = I_0 + I_0 + 2\sqrt{I_0 I_0} \cos\left(\frac{2\pi}{3}\right) \] - Simplifying further: \[ I = 2I_0 + 2I_0 \cos\left(\frac{2\pi}{3}\right) \] - The value of \( \cos\left(\frac{2\pi}{3}\right) \) is \( -\frac{1}{2} \): \[ I = 2I_0 - I_0 = I_0 \] 4. **Conclusion for Assertion**: - Therefore, the assertion is correct: the resultant intensity at the point where the path difference is \( \frac{\lambda}{3} \) is indeed \( I_0 \). 5. **Understanding the Reason**: - The reason states that in interference, the resultant intensity at any point is the average intensity of the two individual intensities. - This is generally true, but it is important to note that the resultant intensity is not simply the average of the two intensities; it also depends on the phase difference between the waves. 6. **Conclusion for Reason**: - The reason is incorrect as stated. The resultant intensity is not merely the average of the two individual intensities; it also includes the interference term that depends on the phase difference. ### Final Conclusion: - The assertion is correct, but the reason is not correctly stated. Therefore, the correct answer is that the assertion is true, but the reason is false.

To solve the question, we need to analyze both the assertion and the reason provided in the context of wave optics, specifically interference. ### Step-by-Step Solution: 1. **Understanding the Assertion**: - The assertion states that two coherent sources transmit waves of equal intensity \( I_0 \), and at a point where the path difference is \( \frac{\lambda}{3} \), the resultant intensity is also \( I_0 \). 2. **Path Difference and Phase Difference**: ...
Promotional Banner

Topper's Solved these Questions

  • WAVE OPTICS

    DC PANDEY ENGLISH|Exercise match column|4 Videos
  • WAVE OPTICS

    DC PANDEY ENGLISH|Exercise medical entrances|42 Videos
  • WAVE OPTICS

    DC PANDEY ENGLISH|Exercise taking it together|47 Videos
  • SOLVED PAPERS 2018

    DC PANDEY ENGLISH|Exercise JIPMER|22 Videos

Similar Questions

Explore conceptually related problems

Two incoherent sources of intensities l and 4l superpose then the resultant intensity is

Two coherent sources each emitting light of intensity I_(0) Interfere, in a medium at a point, where phase different between them is (2pi)/3 . Then, the resultant intensity at that point would be.

Consider interference between waves form two sources of intensities I_(0)&4I_(0) .Find intensities at point where the phase difference is pi

The intensity of interference waves in an interference pattern is same as I_(0) . The resultant intensity at any point of observation will be

Two coherent light beams of intensities I and 4I produce interference pattern. The intensity at a point where the phase difference is zero, will b:

In Young's double slit experiment, the intensity on the screen at a point where path difference is lambda is K. What will be the intensity at the point where path difference is lambda//4 ?

In Young's double slit experiment, the intensity of light at a point on the screen where path difference is lambda is I. If intensity at another point is I/4, then possible path differences at this point are

When two waves of intensities l_1 and l_2 coming from coherent sources interfere at a point P, where phase difference is phi , then resultant intensity (l_(res)) at point P would be

Two incoherent sources of light each with equal intensity I_(0) interfere in a medium . Will any interference pattern be observed ? If no, then why ? Also what would be resultant intensity then ?

In a Young's double slit set up using monochromatic light of wavelength lambda the intensity of light at a point, where path difference is 2lambda is found to be I_(0) What will be the intensity at a point when path different is lambda//3 ?