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A plane polarized light is incident norm...

A plane polarized light is incident normally on a tourmaline plate. Its E vector make an angle of `60^(@)` with the optic axis of the plate. Find the percentage difference between initial and final intensities

A

`50%`

B

`25%`

C

`75%`

D

`90%`

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The correct Answer is:
To solve the problem of finding the percentage difference between the initial and final intensities of plane polarized light incident on a tourmaline plate, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Problem**: We have plane polarized light incident normally on a tourmaline plate. The electric field vector (E vector) makes an angle of \(60^\circ\) with the optic axis of the plate. We need to find the percentage difference between the initial intensity \(I\) and the final intensity \(I'\) after passing through the plate. 2. **Applying Malus's Law**: According to Malus's Law, the intensity of polarized light after passing through a polarizer (in this case, the tourmaline plate) is given by: \[ I' = I \cos^2 \theta \] where \(I\) is the initial intensity, \(I'\) is the final intensity, and \(\theta\) is the angle between the light's electric field vector and the optic axis of the polarizer. 3. **Substituting the Given Values**: Here, \(\theta = 60^\circ\). Therefore, we can calculate \(I'\): \[ I' = I \cos^2(60^\circ) \] We know that \(\cos(60^\circ) = \frac{1}{2}\), so: \[ I' = I \left(\frac{1}{2}\right)^2 = I \cdot \frac{1}{4} \] 4. **Calculating the Final Intensity**: Thus, the final intensity \(I'\) is: \[ I' = \frac{I}{4} \] 5. **Finding the Percentage Difference**: The percentage difference between the initial and final intensities can be calculated using the formula: \[ \text{Percentage Difference} = \frac{I - I'}{I} \times 100 \] Substituting \(I'\) into the equation: \[ \text{Percentage Difference} = \frac{I - \frac{I}{4}}{I} \times 100 \] 6. **Simplifying the Expression**: This simplifies to: \[ \text{Percentage Difference} = \frac{I - \frac{I}{4}}{I} \times 100 = \frac{\frac{4I}{4} - \frac{I}{4}}{I} \times 100 = \frac{\frac{3I}{4}}{I} \times 100 \] The \(I\) cancels out: \[ \text{Percentage Difference} = \frac{3}{4} \times 100 = 75\% \] ### Final Answer: The percentage difference between the initial and final intensities is **75%**.

To solve the problem of finding the percentage difference between the initial and final intensities of plane polarized light incident on a tourmaline plate, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Problem**: We have plane polarized light incident normally on a tourmaline plate. The electric field vector (E vector) makes an angle of \(60^\circ\) with the optic axis of the plate. We need to find the percentage difference between the initial intensity \(I\) and the final intensity \(I'\) after passing through the plate. 2. **Applying Malus's Law**: ...
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