The current of transistor in common emitter mode is 49. The change in collector current and emitter current corresponding to the change in the base current by `5.0 muA`m will be :-

Options

A. `245muA,250muA`
B. `240muA,235muA`
C. `260muA,255muA`
D. None of these

Explanation

To solve the problem step by step, we will use the relationships in a common emitter transistor configuration.

### Step 1: Understand the given data
We are given:
- The change in base current, \( \Delta I_B = 5 \, \mu A \)
- The current gain (beta) of the transistor, \( \beta = 49 \)

### Step 2: Calculate the change in collector current
The relationship between the change in collector current (\( \Delta I_C \)) and the change in base current (\( \Delta I_B \)) is given by the formula:
\[ \Delta I_C = \beta \times \Delta I_B \]
Substituting the values:
\[ \Delta I_C = 49 \times 5 \, \mu A \]
Calculating this:
\[ \Delta I_C = 245 \, \mu A \]

### Step 3: Calculate the change in emitter current
The relationship between the change in emitter current (\( \Delta I_E \)), change in base current (\( \Delta I_B \)), and change in collector current (\( \Delta I_C \)) is given by:
\[ \Delta I_E = \Delta I_B + \Delta I_C \]
Substituting the values we have:
\[ \Delta I_E = 5 \, \mu A + 245 \, \mu A \]
Calculating this:
\[ \Delta I_E = 250 \, \mu A \]

### Final Results
- Change in collector current, \( \Delta I_C = 245 \, \mu A \)
- Change in emitter current, \( \Delta I_E = 250 \, \mu A \)

### Summary
Thus, the changes in the collector and emitter currents corresponding to a change in the base current of \( 5 \, \mu A \) are:
- \( \Delta I_C = 245 \, \mu A \)
- \( \Delta I_E = 250 \, \mu A \)