In the given figure ,C is middle point o...

In the given figure ,C is middle point of line `S_(1)S_(2)`.A monochromatic light of wavelength `gamma` is incident on slits.The ratio of intensites of `S_(3) and S_(4)` is

`oo`

`4:1`

`1:4`

Text Solution

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The correct Answer is:

At `S_(3), trianglex=S_(1)S_(3)-S_(2)S_(3)=0`
`therefore theta = (2pi)/(lamdba) trianglex=0`
`I_(3) =I_(0)+I_(0)+2sqrt(I_(0)xxI_(0)) cos^(@) rArr I_(3)=4I_(0)`
The path difference at `S_(4)` is
`trianglex' =S_(1)S_(4)-S_(2)S_(4)=(dy)/(d)=(d)/(D)=(d)/(D)xx(lambdad)/(2d)=(lambda)/(2) " "(thereforeY)=(lambdaD)/(2d)`
`therefore Phi'=(2pi)/(lambda)xx(lambda)/(2)=pi`
`rArr I_(4)=I_(0)+I_(0)+2I_(0)cospi=0rArr(I_(3))/(I_(4))=(4I_(0))/(0)=oo`

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