A simple telescope consisting of an objective of focal length 60 cm and a single eye lens of focal length 5 cm is focused on a distant object in such a way that parallel rays emerge from eye lens. If the object subtends an angle of `2^(@)` at the objective, the angular width of the image is (Let `tan theta=theta` assuming `theta` small).

Options

A. `10^(@)`
B. `24^(@)`
C. `50^(@)`
D. `(1^(@))/(6)`

Answer

B

Explanation

For telescope
It is a case of normal adjustment
Hence, `M =(F_(0))/(F_(e))also M =beta//alpha`
`Therefore ,(beta)/(alpha)=(f_(0))/(f_(e))`
Here `F_(0)=60 cm F_(e)=5cmrArralpha=2^(@)`
Hence, `beta=24^(@)`