Home
Class 12
PHYSICS
Assertion: A dielectric slabis inserted ...

Assertion: A dielectric slabis inserted between plates of an isolated capacitor. charge on capacitor will remain same.
Reason Charge on an isolated system is conserved.

Text Solution

Verified by Experts

The correct Answer is:
A
Charge of plates remains same as there is no transfer of charge.
Promotional Banner

Topper's Solved these Questions

  • SOLVED PAPERS 2018

    DC PANDEY ENGLISH|Exercise JIPMER|22 Videos

  • SOLVED PAPERS 2018

    DC PANDEY ENGLISH|Exercise AIIMS|22 Videos

  • SOLVED PAPER 2017

    DC PANDEY ENGLISH|Exercise Solved papers 2017(JIPMER)|32 Videos

  • WAVE OPTICS

    DC PANDEY ENGLISH|Exercise For JEE Advanced E. Integer Type Questions|13 Videos

Similar Questions

Explore conceptually related problems

A dielectric slab is inserted between the plates of an isolated capacitor. The force between the plates will

A dielectric slab is inserted between the plates of an isolatted charged capacitor. Which of the following quantities will remain the same?

On placing dielectric slab between the plates of an isolated charged condenser its

A dielectric slab is inserted between the plates of a capacitor. The charge on the capacitor is Q and the magnitude of the induced charge on each surface of the dielectric is Q' .

When a dielectric slab is inserted between the plates of one of the two identical capacitors shown in the figure then match the following:

The electrostatic force between the metal plate of an isolated parallel plate capacitor C having charge Q and area A , is

A dielectric slab is placed between the plates of a parallel plate capacitor. Its capacitance A. become zero B. remains the same C. decrease D. increase

When a dielectric slab is inserted between the plates of one of the two identical capacitors in figure , which of the following properties increase ?

The electrostatic force between the metal plate of an isolated parallel plate capacitro C having charge Q and area A , is

A parallel - plate capacitor of plate area A and plate separation d is charged to a potential difference V and then the battery is disconnected . A slab of dielectric constant K is then inserted between the plate of the capacitor so as to fill the space between the plate .Find the work done on the system in the process of inserting the slab.