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In triangle ABC, angle B = pi//3. " and...

In triangle ABC, `angle B = pi//3. " and " angle C = pi//4 `. Let D divide BC inernally in the ratio `1 : 3 `. Then `(sin angle BAD)/(sin angle CAD)` equals

A

`1/sqrt6`

B

`1/3`

C

`1/sqrt3`

D

`sqrt(2/3)`

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