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In triangle ABC, D is mid point of BC, i...

In triangle ABC, D is mid point of BC, if 'AD' is perpendicular to 'AC then `cos A cos C`

A

`(2(c^(2) - a^(2)))/(3ac)`

B

`((c^(2) - a^(2)))/(3ac)`

C

`(2(c^(2) - a^(2)))/(ac)`

D

`((c^(2) - a^(2)))/(ac)`

Text Solution

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A
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